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	<title>Comments on: Finding the Next Date for Day of Week</title>
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	<link>http://angstrey.com/index.php/2009/04/25/finding-the-next-date-for-day-of-week/</link>
	<description>Another Web Developer blog out of many out there in the blogosphere</description>
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		<title>By: Steve</title>
		<link>http://angstrey.com/index.php/2009/04/25/finding-the-next-date-for-day-of-week/comment-page-1/#comment-4223</link>
		<dc:creator>Steve</dc:creator>
		<pubDate>Mon, 19 Oct 2009 16:14:39 +0000</pubDate>
		<guid isPermaLink="false">http://angstrey.com/?p=174#comment-4223</guid>
		<description>Thank you so much for this solution! Works great!</description>
		<content:encoded><![CDATA[<p>Thank you so much for this solution! Works great!</p>
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		<title>By: Arun</title>
		<link>http://angstrey.com/index.php/2009/04/25/finding-the-next-date-for-day-of-week/comment-page-1/#comment-208</link>
		<dc:creator>Arun</dc:creator>
		<pubDate>Fri, 22 May 2009 08:08:04 +0000</pubDate>
		<guid isPermaLink="false">http://angstrey.com/?p=174#comment-208</guid>
		<description>On the same principles, in DaysToAdd  we could also do:

int n=(d-c);
if (n&lt;=0) n+=7;</description>
		<content:encoded><![CDATA[<p>On the same principles, in DaysToAdd  we could also do:</p>
<p>int n=(d-c);<br />
if (n&lt;=0) n+=7;</p>
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